Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.2 Graph Quadratic Functions in Vertex or Intercept Form - 4.2 Exercises - Mixed Review - Page 251: 70

Answer

$=\begin{bmatrix} 84& 16&108\\ 48 &12 & 56 \end{bmatrix}$

Work Step by Step

Given: $CD=\begin{bmatrix} -1 & 4\\ -2 &3 \end{bmatrix}\begin{bmatrix} 3 & 0 & -1\\ 6 & 1 & 4 \end{bmatrix}$ $=\begin{bmatrix} 21 & 4&17\\ 12 &3 & 14 \end{bmatrix}$ so $4\begin{bmatrix} 21 & 4&17\\ 12 &3 & 14 \end{bmatrix}=\begin{bmatrix} 84& 16&108\\ 48 &12 & 56 \end{bmatrix}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.