Chapter 4 Quadratic Functions and Factoring - 4.2 Graph Quadratic Function in Vertex or Intercept Form - 4.2 Exercises - Skill Practice - Page 249: 12

Option B

We observe that the given function is in the form $y=a(x-h)^2 + k$. We know that $a$ determines how steep the curve is, and we know that if $a$ is positive, the graph faces up, while if $a$ is negative, the graph faces down. Also, we know that the vertex is $(h,k)$. Thus, we see that the vertex is $(-2, -5)$. (Option B)