The graph is attached.
Work Step by Step
Note, in the given graph, the axis of symmetry is the purple line, and the black point is the vertex. We observe that the given function is in the form $y=a(x-h)^2 + k$. We know that $a$ determines how steep the curve is, and we know that if $a$ is positive, the graph faces up, while if $a$ is negative, the graph faces down. Also, we know that the vertex is $(h,k)$.