Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Test - Page 227: 27

Answer

$x=-2, y=3$

Work Step by Step

Write the linear system as a matrix equation $AX = B$. $\begin{bmatrix} 3 & 4\\ 4&5 \end{bmatrix}\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} 6\\ 7 \end{bmatrix}$ Then $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{15-16}\begin{bmatrix} 5 & -4\\ -4 &3 \end{bmatrix}\begin{bmatrix} 6\\ 7 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=-1\begin{bmatrix} 2\\ -3 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -2\\ 3 \end{bmatrix}$ Hence, $x=-2, y=3$
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