Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Test - Page 227: 16

Answer

$\begin{bmatrix} -15&-7\\ 13&15 \end{bmatrix}$

Work Step by Step

$C-3B=\begin{bmatrix} -6&8\\ 10&15 \end{bmatrix}-3\begin{bmatrix} 3&5\\ -1&0 \end{bmatrix}=\begin{bmatrix} -6&8\\ 10&15 \end{bmatrix}-\begin{bmatrix} 9&15\\ -3&0 \end{bmatrix}=\begin{bmatrix} -15&-7\\ 13&15 \end{bmatrix}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.