Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Test - Page 227: 12

Answer

The solution is $(-1,4,2)$.

Work Step by Step

Rewrite the system as a linear system in two variables. Add Equation 1 and Equation 3. Then add Equation 2 to 5 times Equation 3: $ x -y + z = -3$ $4x +2y - z = 2$ _____________________ $5x+y=-1$ $2x - y + 5z = 4$ $20x + 10y - 5z = 10$ __________________________ $22x+9y=14$ Solve the new linear system for both of its variables. $5x+y=-1$ $22x+9y=14$ Add $-9$ times new Equation 1 to new Equation 2: $-45x-9y=9$ $22x+9y=14$ ___________________ $-23x=23$ $x=-1$ Solve for y: $5(-1)+y=-1$ $y=4$ Solve for z: $-1-4+z=-3$ $z=2$ The solution is $(-1,4,2)$.
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