Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Quiz for Lessons 3.6-3.8 - Page 217: 11

Answer

$x=0, y=4$

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} 3 & -1\\ 2 & -2 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -4\\ -8 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{-6+2}\begin{bmatrix} -2&1\\ -2 & 3 \end{bmatrix}.\begin{bmatrix} -4\\ -8 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=-\frac{1}{4}\begin{bmatrix} 0\\ -16 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} 0\\ 4 \end{bmatrix}$ Hence, $x=0, y=4$
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