Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Quiz for Lessons 3.6-3.8 - Page 217: 10

Answer

$x=\frac{17}{3}, y=2$

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} -3 & 2\\ 6 & -5 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -13\\ 24 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{15-12}\begin{bmatrix} -5&-2\\ -6 & -3 \end{bmatrix}.\begin{bmatrix} -13\\ 24 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{3}\begin{bmatrix} 17\\ 6 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} \frac{17}{3}\\ 2 \end{bmatrix}$ Hence, $x=\frac{17}{3}, y=2$
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