Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Skill Practice - Page 165: 44


Thus $x=16,y=14$

Work Step by Step

$0.02x-0.05y=-0.38\\-0.03x+0.075y=0.57$ Then adding this to the second equation we get: $0.115y=1.61\\y=14$ Then $0.02x-0.05(14)=-0.38\\0.02x=0.32\\x=16$
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