## Algebra 2 (1st Edition)

Thus $x=16,y=14$
$0.02x-0.05y=-0.38\\-0.03x+0.075y=0.57$ Then adding this to the second equation we get: $0.115y=1.61\\y=14$ Then $0.02x-0.05(14)=-0.38\\0.02x=0.32\\x=16$