Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Skill Practice - Page 165: 40

Answer

Option B

Work Step by Step

Solving the equation using substitution, we find: $$6\cdot \frac{4-2y}{3}-3y=-27 \\ y=5$$ Thus: $$x=\frac{4-2\cdot \:5}{3}=-2$$
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