Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 2 Linear Equations and Functions - 2.1 Represent Relations and Functions - 2.1 Exercises - Skill Practice - Page 78: 39



Work Step by Step

For starters, the function is linear, for the slope is a constant value ($-\frac{2}{3}$). We now evaluate $f(8)$: $$h(15) = 7 -\frac{2}{3}(15) \\ h(15) = 7-10 \\ h(15) =-3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.