Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 2 Linear Equations and Functions - 2.1 Represent Relations and Functions - 2.1 Exercises - Skill Practice - Page 78: 36



Work Step by Step

For starters, the function is not linear, for the absolute value term causes the slope not to be constant. We now evaluate $f(-4)$: $$ f(-4) = \mid -4 \mid +10 = 4+10 =14$$
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