## Algebra 2 (1st Edition)

$y =3 \sin 2x$
General solution for Trigonometric functions $sine$ and $cosine$ that model a sinusoid is as follows: $y=A \sin B (x-h) +k$ and $y=A \cos B (x-h)+k$ We can see from the graph that it passes through the origin and defines the $Sine$ function. Here, the amplitude is $a=3$, that is $3 \sin$ Since, the time period for a trigonometric function is $2 \pi/b$ and here $B=2$ Thus, we have $y =3 \sin 2x$