Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.5 Write Trigonometric Functions and Models - 14.5 Exercises - Skill Practice - Page 944: 3

Answer

$y =3 \sin 2x$

Work Step by Step

General solution for Trigonometric functions $sine$ and $cosine$ that model a sinusoid is as follows: $y=A \sin B (x-h) +k $ and $y=A \cos B (x-h)+k$ We can see from the graph that it passes through the origin and defines the $Sine$ function. Here, the amplitude is $a=3$, that is $3 \sin $ Since, the time period for a trigonometric function is $2 \pi/b$ and here $B=2$ Thus, we have $y =3 \sin 2x$
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