Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.5 Write Trigonometric Functions and Models - 14.5 Exercises - Skill Practice - Page 944: 11

Answer

$y= 4 -\cos 3x$

Work Step by Step

General solution for Trigonometric functions $sine$ and $cosine$ that model a sinusoid is as follows: $y=A \sin B (x-h) +k $ and $y=A \cos B (x-h)+k$ Amplitude, $|a|= \dfrac{M-m}{2}= \dfrac{5-3}{2}= \dfrac{2}{2}$ Thus, we have $|a|=1$ Vertical amplitude, $k= \dfrac{M+m}{2}= \dfrac{5+3}{2}$ This gives: $|k|=\dfrac{8}{2}=4$ Therefore, the period is: $P=2( \dfrac{\pi}{3}-0) =\dfrac{2 \pi}{3}$ and $\dfrac{2 \pi}{a}=\dfrac{2 \pi}{3} \implies a=3$ Hence, the function is: $y= 4 -\cos 3x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.