## Algebra 2 (1st Edition)

$-\dfrac{\sqrt 3}{2}$
The Trigonometric Identities are written below: $\sin \theta=\dfrac{Opposite}{Hypotenuse}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}$ $\tan \theta=\dfrac{Opposite}{Adjacent}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}$ $\cot \theta=\dfrac{Adjacent}{Opposite}$ Hence, our required answer is: $-\dfrac{\sqrt 3}{2}$