Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.5 Write Trigonometric Functions and Models - 14.5 Exercises - Mixed Review - Page 947: 31

Answer

$y^2=-16x$

Work Step by Step

a) The general form of the equation of a parabola with vertex at $(0,0)$ is given by $x^2=4py$ and the focus is: $F:(0,p)$ b) The general form of the equation of a parabola with vertex at $(0,0)$ is given by $y^2=4px$ and the focus is: $F:(p,0)$ For the given problem, we have $y^2=-16x$
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