Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - Chapter Test - Page 901: 21

Answer

See below.

Work Step by Step

$C=180-26-77=77^\circ$. Using the law of sines, $\frac{a}{\sin26^\circ}=\frac{50}{\sin77^\circ}\\a=\frac{50\sin26^\circ}{\sin77^\circ}\approx22.5$ $\frac{b}{\sin77^\circ}=\frac{50}{\sin77^\circ}\\b=\frac{50\sin77^\circ}{\sin77^\circ}=50$
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