Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - Chapter Test - Page 901: 16

Answer

See below.

Work Step by Step

$B=180-47-32=101^\circ$. Using the law of sines, $\frac{a}{\sin47^\circ}=\frac{12}{\sin32^\circ}\\a=\frac{12\sin47^\circ}{\sin32^\circ}\approx16.56$ $\frac{b}{\sin101^\circ}=\frac{12}{\sin32^\circ}\\b=\frac{12\sin101^\circ}{\sin32^\circ}\approx22.23$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.