Chapter 13, Trigonometric Ratios and Functions - 13.6 Apply the Law of Cosines - 13.6 Exercises - Quiz for Lessons 13.5-13.6 - Page 894: 8

See below.

$C=180-A-B=180-112-48=20^\circ$. Using the law of sines, $\frac{a}{\sin112^\circ}=\frac{5}{\sin20^\circ}\\a=\frac{5\sin112^\circ}{\sin20^\circ}\approx13.56$ $\frac{b}{\sin48^\circ}=\frac{5}{\sin20^\circ}\\a=\frac{5\sin48^\circ}{\sin20^\circ}\approx10.86$