Answer
See below.
Work Step by Step
$B=180-A-C=180-102-25=53^\circ$.
Using the law of sines, $\frac{b}{\sin53^\circ}=\frac{31}{\sin102^\circ}\\b=\frac{31\sin53^\circ}{\sin102^\circ}\approx25.31$
$\frac{c}{\sin25^\circ}=\frac{31}{\sin102^\circ}\\c=\frac{31\sin25^\circ}{\sin102^\circ}\approx13.39$