Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.6 Apply the Law of Cosines - 13.6 Exercises - Quiz for Lessons 13.5-13.6 - Page 894: 5

Answer

See below.

Work Step by Step

$B=180-A-C=180-102-25=53^\circ$. Using the law of sines, $\frac{b}{\sin53^\circ}=\frac{31}{\sin102^\circ}\\b=\frac{31\sin53^\circ}{\sin102^\circ}\approx25.31$ $\frac{c}{\sin25^\circ}=\frac{31}{\sin102^\circ}\\c=\frac{31\sin25^\circ}{\sin102^\circ}\approx13.39$
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