Algebra 2 (1st Edition)

Published by McDougal Littell

Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.4 Exercises - Problem Solving - Page 879: 39

Answer

$\theta =\tan^{-1} (\dfrac{44t}{100})$ or, $\tan^{-1} (\dfrac{11t}{25})$

Work Step by Step

Remember: $30 mph= 44 ft/sec$ Now, $\tan \theta= 44t \times \dfrac{1}{100}=\dfrac{44t}{100}$ Re-write as: $\theta = \tan^{-1} (\dfrac{44t}{100})$ This implies that $\theta =\tan^{-1} (\dfrac{44t}{100})$ or, $\tan^{-1} (\dfrac{11t}{25})$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.