## Algebra 2 (1st Edition)

$7.01$ ft
We have the ratio of $\dfrac{\sin \theta_1 }{\sin \theta_2 }=1.333$ Now, $\dfrac{\sin 70^{\circ} }{\sin \theta_2 }=1.333$ Re-write as: $\theta_2 = \sin^{-1} [ \dfrac{\sin 70^{\circ} }{1.333}]$ This implies that $\theta_2 \approx 44.83^{\circ}$ Now, $x = 4 \tan \theta_2 =4 \tan 44.83^{\circ} \approx 3.98$ft and $y = 4 \tan \theta_1 =4 \tan 70^{\circ} \approx 10.99$ft Further, $d = y-x = 10.99 -3.98 =7.01$ ft