Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Skill Practice - Page 871: 26



Work Step by Step

When $P$ is the period of $f(x)$ then we have $ f(x+p)=f(x)$ Here, we have $\sin \theta=-150^{\circ}$ and $ \sin (-150^{\circ})=\sin [(-150^{\circ})^{\circ}+360^{\circ})=\sin 210^{\circ}$ and $\theta'= 210^{\circ}- 180^{\circ}= 30^{\circ}$ $\sin 30^{\circ}=\dfrac{1}{2}$ Since the function sine is negative in the third quadrant: Thus, $-\sin 30^{\circ}=-\dfrac{1}{2}$
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