Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Skill Practice - Page 871: 25

Answer

$\sqrt 3$

Work Step by Step

When $P$ is the period of $f(x)$ then we have $ f(x+p)=f(x)$ Here, we have $\tan \theta=180^{\circ}$ and $ \tan 240^{\circ}=\tan (180^{\circ}+60^{\circ})=\tan 60^{\circ}= \sqrt 3$
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