Answer
$16$
Work Step by Step
$\sum_{i=1}^{\infty} 8 (\dfrac{1}{2})^{i-1}=(8) \times [\dfrac{1-0.5^{\infty}}{1-0.5}]$
$=(8) \times [\dfrac{1-0.5^{\infty}}{1-0.5}]$
$=(8) \times [\dfrac{1}{0.5}]$
$=16$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Mixed Review - Page 872: 56
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