#### Answer

$242$

#### Work Step by Step

$\sum_{i=1}^{5} 2(3^{i-1})=2 \times [\dfrac{3^6-1}{3-1}]$
$=2 \times [\dfrac{3^5-1}{3-1}]$
$=2 \times [\dfrac{243-1}{3-1}]$
$=2 \times [\dfrac{242}{2}]$
$=242$

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

$242$

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