## Algebra 2 (1st Edition)

$59$ meters
Let $h$ be the height of the building. $h=\dfrac{50}{(\cot 32^{\circ}-\cot 53^{\circ})}$ This gives: $h=\dfrac{50}{(1.6000335-0.753554)}$ $h \approx 59$ meters Hence, the height of the building is $59$ meters.