Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Problem Solving - Page 858: 37


$59$ meters

Work Step by Step

Let $h$ be the height of the building. $h=\dfrac{50}{(\cot 32^{\circ}-\cot 53^{\circ})}$ This gives: $h=\dfrac{50}{(1.6000335-0.753554)}$ $h \approx 59$ meters Hence, the height of the building is $59$ meters.
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