## Algebra 2 (1st Edition)

$53612.7 ft$
Let $x$ be the horizontal distance of the airplane from town $1$. Here,we have $\tan 65^{\circ}=\dfrac{25000 ft}{x}$ This gives: $x=25,000 \times \cot 25^{\circ}$ Now, $x=53612.7 ft$