## Algebra 2 (1st Edition)

$H \approx 100.26 ft$ and $L \approx 170.58 ft$
Here, we have $\tan 36^{\circ}=\dfrac{Hypotensue(H)}{138}$ This gives: $H \approx 100.26 ft$ and $\cos 36^{\circ}=\dfrac{138}{Length(L)}$ This gives: $L \approx 170.58 ft$ Hence, $H \approx 100.26 ft$ and $L \approx 170.58 ft$