## Algebra 2 (1st Edition)

$63.39 cm$
Let us consider $x$ to be the distance. Since, $\sin \theta=\dfrac{Opposite}{Hypotensue}=\dfrac{x}{150}$ or, $\sin 25^{\circ}=\dfrac{x}{150}$ This gives: $x =150 \sin 25^{\circ}$ or, $x \approx 63.39 cm$