Answer
$(x+4)^2=-4(y+3)$; Parabola
Work Step by Step
Given: $x^2+8x+4y+28=0$
$(x+4)^2 +4y+28-16=0$
This gives:
$(x+4)^2=-(4y+12)$
Thus, we have
$(x+4)^2=-4(y+3)$
This is the standard form of a Parabola.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Mixed Review - Page 858: 54
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