Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Mixed Review - Page 858: 54


$(x+4)^2=-4(y+3)$; Parabola

Work Step by Step

Given: $x^2+8x+4y+28=0$ $(x+4)^2 +4y+28-16=0$ This gives: $(x+4)^2=-(4y+12)$ Thus, we have $(x+4)^2=-4(y+3)$ This is the standard form of a Parabola.
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