## Algebra 2 (1st Edition)

$x=2; y=-3$
Since we are given two equations $4x+3y=-1$ and $3x+y=3$ Now, multiply the equation $3x+y=3$ by $-3$. we have $4x+3y=-1$ and $-9x-3y=-9$ After solving, we get $-5x=-10 \implies x=2$ Then, $4(2)+3y=-1$ This implies $10+3y=-1 \implies y=-3$ Hence, $x=2; y=-3$