Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 849: 51


See below.

Work Step by Step

According to the exercise: $a_1=31000$ and $a_n=a_{n-1}+1600$ for $2\leq n\leq 9$. Then $a_9=(9-1)1600+31000=43800$.
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