Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 849: 46

Answer

See below.

Work Step by Step

$I=\sqrt{\frac{P}{R}}\\I^2=\frac{P}{R}\\P=I^2R=17^2\cdot6.5=1878.5$
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