Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Chapter Review - Page 842: 29

Answer

$\frac{182}{333}$

Work Step by Step

$0.546546...=546(0.001)+546(0.001)^2+...=\frac{a_1}{1-r}=\frac{546(0.001)}{1-0.001}=\frac{0.546}{0.999}=\frac{182}{333}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.