Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Chapter Review - Page 842: 30

Answer

$\frac{25}{66}$

Work Step by Step

$0.37878...=0.3+7.8(0.01)+7.8(0.01)^2+...=0.3+\frac{a_1}{1-r}=0.3+\frac{7.8(0.01)}{1-0.01}=\frac{25}{66}$
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