Answer
$\dfrac{x^{5}-1}{x-1}$
Work Step by Step
Here, we have a common ratio $r=x$ and $a_1= 1$
We are given that $S_5= (1) \sum_{i=1}^5 x^{i-1}$
We know that $S_{n}=a_1(\dfrac{r^{n}-1}{r-1})$
Common ratio $r=x$ and $a_1= 1$
Plug in $n=5$
Hence, $S_{5}=\dfrac{x^{5}-1}{x-1}$