## Algebra 2 (1st Edition)

$5115$
Here, we have $a_n=5(2)^{i-1}$ and $a_1=5(2)^{1-1}=5$ Common ratio $r=2$ Now, $S_{10}=a_1(\dfrac{1-r^{10}}{1-r})$ or, $S_{10}=5 \times (\dfrac{1-2^{10}}{1-2})$ or, $S_{10}=5 \times (\dfrac{1-1024}{-1})=5115$