Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Skill Practice - Page 814: 30

Answer

See below

Work Step by Step

The sequence is geometric with first term $a_2=6$ and common ratio $r=2$. So, a rule for the nth term is:$$a_n=a_2r^{n-2}=6.(2)^{n-2}=3*2^{n-1}$$ The first 6 terms are $a_1=3\\a_2=6\\a_3=12\\a_4=24\\a_5=48\\a_6=96$
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