Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Skill Practice - Page 814: 23


$a_n=-2(0.4)^{n-1}$ and $a_7=-0.008192$

Work Step by Step

The nth term is given by $a_n= a_1 r^{n-1}$ ...(1) Here, $a_1=-2; r=\dfrac{a_2}{a_1}=\dfrac{-0.8}{-2}=0.4$ From equation (1), we have $a_n=-2(0.4)^{n-1}$ Plug in $n=7$ $a_7=-2(0.4)^{7-1}=-0.008192$ Hence, $a_n=-2(0.4)^{n-1}$ and $a_7=-0.008192$
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