Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.4 Select and Draw Conclusions from Samples - 11.4 Exercises - Skill Practice - Page 770: 18

Answer

567

Work Step by Step

We use the margin of error equation to find: $$margin\ of \ error = \frac{1}{\sqrt{n}}\\ n=(margin\ of \ error)^{-2} \\ n=(.042)^{-2} \\ n=567$$
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