#### Answer

1111

#### Work Step by Step

We use the margin of error equation to find:
$$margin\ of \ error =\times \frac{1}{\sqrt{n}}\\ n=(margin\ of \ error)^{-2} \\ n=(.03)^{-2} \\ n=1111$$

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

1111

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