Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is included:
$\bar x=\frac{65+173+181+184+188+190+192+199}{8}=171.5\\ Median =186\\Mode =none\\Range=134\\\sigma =\sqrt \frac{(65-171.5)^2+(173-171.5)^2+(181-171.5)^2+(184-171.5)^2+(188-171.5)^2+(190-171.5)^2+(192-171.5)^2+(199-171.5)^2}{8}=40.9$
The mean, median, mode, range, and standard deviation of the data set when the outlier is not included:
$\bar x=\frac{173+181+184+188+190+192+199}{7}=186.71\\ Median =188\\Mode =none\\Range=26\\\sigma =\sqrt \frac{(173-186.71)^2+(181-186.71)^2+(184-186.71)^2+(188-186.71)^2+(190-186.71)^2+(192-186.71)^2+(199-186.71)^2}{8}=7.74$