Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.1 Find Measures of Central Tendency and Dispersion - 11.1 Exercises - Skill Practice - Page 747: 16

Answer

See below.

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the mean is: $\frac{301+312+308+320+318+315+325+336}{8}=316.875$ Hence here the range is: $336-301=35$, and the standard deviation is: $\sqrt{\frac{(301-316.875)^2+(312-316.875)^2+...+(336-316.875)^2}{8}}\approx10.696$
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