Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - Chapter Review - Page 736: 24

Answer

See below.

Work Step by Step

a) In this case the events are independent: $\frac{3}{16}\frac{5}{16}=\frac{15}{256}$ b) In this case the events are not independent: the first one has probability $\frac{3}{16}$, and the second one has probability $\frac{5}{15}$; thus the probability is: $\frac{3}{16}\frac{5}{15}=\frac{1}{16}$
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