Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - Chapter Review - Page 736: 23


See below.

Work Step by Step

a) In this case the events are independent: $\frac{5}{16}\frac{8}{16}=\frac{5}{32}$ b) In this case the events are not independent: the first one has probability $\frac{5}{16}$, and the second one has probability $\frac{8}{15}$. Thus the probability is: $\frac{5}{16}\frac{8}{15}=\frac{1}{6}$
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