## Algebra 2 (1st Edition)

$3.77×10^{−16}$
The chance of doing a specific problem correctly by guessing is $1/4$ Then, the number of ways to choose which ones are correct is dictated by $_{30}C_n$. where n is the number of correct OR incorrect (it doesn't matter because they will add up to 30 either way. $$_{30}C_2*(1/4)^{30}=\boxed{3.77×10^{−16} }$$