Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.6 Construct and Interpret Binomial Distributions - 10.6 Exercises - Skill Practice - Page 728: 21

Answer

$$\boxed{4.74*10^{−11} }$$

Work Step by Step

The chance of doing a specific problem correctly by guessing is $1/4$ Then, the number of ways to choose which ones are correct is dictated by $_{30}C_n$ where n is the number of correct OR incorrect (it doesn't matter because they will add up to 30 either way. $$_{30}C_{11}*(1/4)^{30}=\boxed{4.74*10^{−11} }$$
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