## Algebra 2 (1st Edition)

$\approx0.868$
Following the example: $P(\text{not hearing song})=\frac{_{11}C_4}{_{12}C_4}$ Hearing the songs on each day is independent, hence the probability we are looking for is: $P(\text{hearing song})=1-(\frac{_{11}C_4}{_{12}C_4})^5\approx0.868$