Algebra 2 (1st Edition)

$\frac{27}{1000}$
Let events $A$, $B$, and $C$ be getting a perfect square in the first, second, and third spins, respectively. The three events are independent. The probability of getting a perfect square in each of the spins is $\frac{3}{10}$ because there are $3$ perfect squares out of the first ten integers. Hence the probability: $P(\text{A and B and C})=P(A)P(B)(P(C)=\frac{3}{10}\frac{3}{10}\frac{3}{10}=\frac{27}{1000}$